20Q^(-1/2)=5

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Solution for 20Q^(-1/2)=5 equation: 


D( Q )

Q < 0

Q = 0

Q < 0

Q = 0

Q = 0

Q in (0:+oo)

20*Q^(-1/2) = 5 // - 5

20*Q^(-1/2)-5 = 0

20*Q^(-1/2) = 5 // : 20

Q^(-1/2) = 1/4

-1/2 < 0

1/(Q^(1/2)) = 1/4 // * Q^(1/2)

1 = 1/4*Q^(1/2) // : 1/4

4 = Q^(1/2)

Q^(1/2) = 4 // ^ 2

Q = 16

Q = 16

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